How would you choose to reduce the system shown to a 2 × 2? Explain why you would choose this approach. –3x + y – 2z = 10 (1) 5x – 2y – 2z = 12 (2) x – y + z = 23 (3)
Accepted Solution
A:
-3x + y - 2z = 10 |* -1 3x - y +2z = -10 5x -2y -2z = 12 --------------------------- I add these equations term by term 8x - 3y = 2
-3x + y - 2z =10 ⇒ -3x + y - 2z =10 x -y +z = 23 | *2 2x - 2y + 2z = 46 ----------------------------- I add these eq. -x -y = 56
8x - 3y = 2 -x -y = 56
this is the system after i reduce it ( it has only two variables x and y)